Optimal. Leaf size=601 \[ -\frac{b^{3/2} \left (46 a^2 A b^3+63 a^4 A b-6 a^3 b^2 B-35 a^5 B-3 a b^4 B+15 A b^5\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} d \left (a^2+b^2\right )^3}+\frac{\left (3 a^2 b (A+B)+a^3 (A-B)-3 a b^2 (A-B)-b^3 (A+B)\right ) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}-\frac{\left (3 a^2 b (A+B)+a^3 (A-B)-3 a b^2 (A-B)-b^3 (A+B)\right ) \tan ^{-1}\left (\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}+\frac{b \left (13 a^2 A b-9 a^3 B-a b^2 B+5 A b^3\right )}{4 a^2 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{b (A b-a B)}{2 a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}-\frac{31 a^2 A b^2+8 a^4 A-11 a^3 b B-3 a b^3 B+15 A b^4}{4 a^3 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)}}+\frac{\left (3 a^2 b (A-B)+a^3 (-(A+B))+3 a b^2 (A+B)-b^3 (A-B)\right ) \log \left (\tan (c+d x)-\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3}-\frac{\left (3 a^2 b (A-B)+a^3 (-(A+B))+3 a b^2 (A+B)-b^3 (A-B)\right ) \log \left (\tan (c+d x)+\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3} \]
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Rubi [A] time = 1.69065, antiderivative size = 601, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 13, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.394, Rules used = {3609, 3649, 3653, 3534, 1168, 1162, 617, 204, 1165, 628, 3634, 63, 205} \[ -\frac{b^{3/2} \left (46 a^2 A b^3+63 a^4 A b-6 a^3 b^2 B-35 a^5 B-3 a b^4 B+15 A b^5\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} d \left (a^2+b^2\right )^3}+\frac{\left (3 a^2 b (A+B)+a^3 (A-B)-3 a b^2 (A-B)-b^3 (A+B)\right ) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}-\frac{\left (3 a^2 b (A+B)+a^3 (A-B)-3 a b^2 (A-B)-b^3 (A+B)\right ) \tan ^{-1}\left (\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{\sqrt{2} d \left (a^2+b^2\right )^3}+\frac{b \left (13 a^2 A b-9 a^3 B-a b^2 B+5 A b^3\right )}{4 a^2 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{b (A b-a B)}{2 a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}-\frac{31 a^2 A b^2+8 a^4 A-11 a^3 b B-3 a b^3 B+15 A b^4}{4 a^3 d \left (a^2+b^2\right )^2 \sqrt{\tan (c+d x)}}+\frac{\left (3 a^2 b (A-B)+a^3 (-(A+B))+3 a b^2 (A+B)-b^3 (A-B)\right ) \log \left (\tan (c+d x)-\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3}-\frac{\left (3 a^2 b (A-B)+a^3 (-(A+B))+3 a b^2 (A+B)-b^3 (A-B)\right ) \log \left (\tan (c+d x)+\sqrt{2} \sqrt{\tan (c+d x)}+1\right )}{2 \sqrt{2} d \left (a^2+b^2\right )^3} \]
Antiderivative was successfully verified.
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Rule 3609
Rule 3649
Rule 3653
Rule 3534
Rule 1168
Rule 1162
Rule 617
Rule 204
Rule 1165
Rule 628
Rule 3634
Rule 63
Rule 205
Rubi steps
\begin{align*} \int \frac{A+B \tan (c+d x)}{\tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))^3} \, dx &=\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{\int \frac{\frac{1}{2} \left (4 a^2 A+5 A b^2-a b B\right )-2 a (A b-a B) \tan (c+d x)+\frac{5}{2} b (A b-a B) \tan ^2(c+d x)}{\tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))^2} \, dx}{2 a \left (a^2+b^2\right )}\\ &=\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{\int \frac{\frac{1}{4} \left (8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B\right )-2 a^2 \left (2 a A b-a^2 B+b^2 B\right ) \tan (c+d x)+\frac{3}{4} b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right ) \tan ^2(c+d x)}{\tan ^{\frac{3}{2}}(c+d x) (a+b \tan (c+d x))} \, dx}{2 a^2 \left (a^2+b^2\right )^2}\\ &=-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\int \frac{\frac{1}{8} \left (24 a^4 A b+31 a^2 A b^3+15 A b^5-8 a^5 B-3 a^3 b^2 B-3 a b^4 B\right )+a^3 \left (a^2 A-A b^2+2 a b B\right ) \tan (c+d x)+\frac{1}{8} b \left (8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B\right ) \tan ^2(c+d x)}{\sqrt{\tan (c+d x)} (a+b \tan (c+d x))} \, dx}{a^3 \left (a^2+b^2\right )^2}\\ &=-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\int \frac{a^3 \left (3 a^2 A b-A b^3-a^3 B+3 a b^2 B\right )+a^3 \left (a^3 A-3 a A b^2+3 a^2 b B-b^3 B\right ) \tan (c+d x)}{\sqrt{\tan (c+d x)}} \, dx}{a^3 \left (a^2+b^2\right )^3}-\frac{\left (b^2 \left (63 a^4 A b+46 a^2 A b^3+15 A b^5-35 a^5 B-6 a^3 b^2 B-3 a b^4 B\right )\right ) \int \frac{1+\tan ^2(c+d x)}{\sqrt{\tan (c+d x)} (a+b \tan (c+d x))} \, dx}{8 a^3 \left (a^2+b^2\right )^3}\\ &=-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{2 \operatorname{Subst}\left (\int \frac{a^3 \left (3 a^2 A b-A b^3-a^3 B+3 a b^2 B\right )+a^3 \left (a^3 A-3 a A b^2+3 a^2 b B-b^3 B\right ) x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{a^3 \left (a^2+b^2\right )^3 d}-\frac{\left (b^2 \left (63 a^4 A b+46 a^2 A b^3+15 A b^5-35 a^5 B-6 a^3 b^2 B-3 a b^4 B\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} (a+b x)} \, dx,x,\tan (c+d x)\right )}{8 a^3 \left (a^2+b^2\right )^3 d}\\ &=-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\left (b^2 \left (63 a^4 A b+46 a^2 A b^3+15 A b^5-35 a^5 B-6 a^3 b^2 B-3 a b^4 B\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+b x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{4 a^3 \left (a^2+b^2\right )^3 d}-\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \operatorname{Subst}\left (\int \frac{1-x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{\left (a^2+b^2\right )^3 d}-\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \operatorname{Subst}\left (\int \frac{1+x^2}{1+x^4} \, dx,x,\sqrt{\tan (c+d x)}\right )}{\left (a^2+b^2\right )^3 d}\\ &=-\frac{b^{3/2} \left (63 a^4 A b+46 a^2 A b^3+15 A b^5-35 a^5 B-6 a^3 b^2 B-3 a b^4 B\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} \left (a^2+b^2\right )^3 d}-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{2}+2 x}{-1-\sqrt{2} x-x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}+\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{2}-2 x}{-1+\sqrt{2} x-x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \operatorname{Subst}\left (\int \frac{1}{1-\sqrt{2} x+x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \left (a^2+b^2\right )^3 d}-\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \operatorname{Subst}\left (\int \frac{1}{1+\sqrt{2} x+x^2} \, dx,x,\sqrt{\tan (c+d x)}\right )}{2 \left (a^2+b^2\right )^3 d}\\ &=-\frac{b^{3/2} \left (63 a^4 A b+46 a^2 A b^3+15 A b^5-35 a^5 B-6 a^3 b^2 B-3 a b^4 B\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} \left (a^2+b^2\right )^3 d}+\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \log \left (1-\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \log \left (1+\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}-\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}+\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}\\ &=\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \tan ^{-1}\left (1-\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{\left (a^3 (A-B)-3 a b^2 (A-B)+3 a^2 b (A+B)-b^3 (A+B)\right ) \tan ^{-1}\left (1+\sqrt{2} \sqrt{\tan (c+d x)}\right )}{\sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{b^{3/2} \left (63 a^4 A b+46 a^2 A b^3+15 A b^5-35 a^5 B-6 a^3 b^2 B-3 a b^4 B\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{4 a^{7/2} \left (a^2+b^2\right )^3 d}+\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \log \left (1-\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{\left (3 a^2 b (A-B)-b^3 (A-B)-a^3 (A+B)+3 a b^2 (A+B)\right ) \log \left (1+\sqrt{2} \sqrt{\tan (c+d x)}+\tan (c+d x)\right )}{2 \sqrt{2} \left (a^2+b^2\right )^3 d}-\frac{8 a^4 A+31 a^2 A b^2+15 A b^4-11 a^3 b B-3 a b^3 B}{4 a^3 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)}}+\frac{b (A b-a B)}{2 a \left (a^2+b^2\right ) d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{b \left (13 a^2 A b+5 A b^3-9 a^3 B-a b^2 B\right )}{4 a^2 \left (a^2+b^2\right )^2 d \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}\\ \end{align*}
Mathematica [C] time = 6.26299, size = 585, normalized size = 0.97 \[ \frac{b (A b-a B)}{2 a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))^2}+\frac{\frac{\frac{1}{2} b^2 \left (4 a^2 A-a b B+5 A b^2\right )+\frac{9}{2} a^2 b (A b-a B)}{a d \left (a^2+b^2\right ) \sqrt{\tan (c+d x)} (a+b \tan (c+d x))}+\frac{-\frac{31 a^2 A b^2+8 a^4 A-11 a^3 b B-3 a b^3 B+15 A b^4}{2 a d \sqrt{\tan (c+d x)}}-\frac{2 \left (\frac{2 \left (a^4 (-b) \left (a^2 A+2 a b B-A b^2\right )+\frac{1}{8} a^2 b \left (31 a^2 A b^2+8 a^4 A-11 a^3 b B-3 a b^3 B+15 A b^4\right )+\frac{1}{8} b^2 \left (31 a^2 A b^3+24 a^4 A b-3 a^3 b^2 B-8 a^5 B-3 a b^4 B+15 A b^5\right )\right ) \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a}}\right )}{\sqrt{a} \sqrt{b} d \left (a^2+b^2\right )}+\frac{-\frac{\sqrt [4]{-1} \left (a^3 \left (3 a^2 A b+a^3 (-B)+3 a b^2 B-A b^3\right )-i a^3 \left (a^3 A+3 a^2 b B-3 a A b^2-b^3 B\right )\right ) \tan ^{-1}\left ((-1)^{3/4} \sqrt{\tan (c+d x)}\right )}{d}-\frac{\sqrt [4]{-1} \left (a^3 \left (3 a^2 A b+a^3 (-B)+3 a b^2 B-A b^3\right )+i a^3 \left (a^3 A+3 a^2 b B-3 a A b^2-b^3 B\right )\right ) \tanh ^{-1}\left ((-1)^{3/4} \sqrt{\tan (c+d x)}\right )}{d}}{a^2+b^2}\right )}{a}}{a \left (a^2+b^2\right )}}{2 a \left (a^2+b^2\right )} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.067, size = 1864, normalized size = 3.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.65004, size = 1092, normalized size = 1.82 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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